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Learning Task 1: Calculate the mass percent of each element in a compound. Write

your solution in a separate sheet of paper.

Calculate the percent by mass of each element in the following compounds:

1. Methane, CH4 (C = 12.01 g/mol; H = 1.008 g/mol)

2. Sodium Nitrate, NaNO3 (Na = 23.0 g/mol; N = 14.0 g/mol; O = 16.0 g/mol)​

Sagot :

Solution (Problem 1)

Step 1: Calculate the molar mass of CH₄.

molar mass = (12.01 g/mol × 1) + (1.008 g/mol × 4)

molar mass = 16.042 g/mol

Step 2: Calculate the mass percent of each element in CH₄.

For %C

[tex]\% \: \text{C} = \frac{\text{12.01 g/mol × 1}}{\text{16.042 g/mol}} × 100[/tex]

[tex]\boxed{\% \: \text{C} = 74.87\%}[/tex]

For %H

[tex]\% \: \text{H} = \frac{\text{1.008 g/mol × 4}}{\text{16.042 g/mol}} × 100[/tex]

[tex]\boxed{\% \: \text{H} = 25.13\%}[/tex]

Solution (Problem 2)

Step 1: Calculate the molar mass of NaNO₃.

molar mass = (23.0 g/mol × 1) + (14.0 g/mol × 1) + (16.0 g/mol × 3)

molar mass = 85.0 g/mol

Step 2: Calculate the mass percent of each element in NaNO₃.

For %Na

[tex]\% \: \text{Na} = \frac{\text{23.0 g/mol × 1}}{\text{85.0 g/mol}} × 100[/tex]

[tex]\boxed{\% \: \text{Na} = 27.06\%}[/tex]

For %N

[tex]\% \: \text{N} = \frac{\text{14.0 g/mol × 1}}{\text{85.0 g/mol}} × 100[/tex]

[tex]\boxed{\% \: \text{N} = 16.47\%}[/tex]

For %O

[tex]\% \: \text{O} = \frac{\text{16.0 g/mol × 3}}{\text{85.0 g/mol}} × 100[/tex]

[tex]\boxed{\% \: \text{O} = 56.47\%}[/tex]

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