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Jose stands 420 meters from the base of the building. If the top of the building forms 90 degrees with Jose and the base, what is the height of the building

Sagot :

Answer:

the answer is 330 that is the one i only know

Question: Jose stands 420 meters from the base of the building. If the top of the building forms 75 degrees with Jose and the base, what is the height of the building?

Answer:

1567.44 meters

Step-by-step explanation:

[tex]\tan \rm \alpha = \frac{opposite}{adjacent}[/tex]

[tex]\implies \rm \tan 75^{\circ} = \frac{height}{420}[/tex]

[tex]\implies \rm 2 + \sqrt{3} = \frac{height}{420}[/tex]

[tex]\implies \rm 420(2+\sqrt{3}) = height[/tex]

[tex]\implies \rm 840 + 420\sqrt{3} = height[/tex]

[tex]\implies \boxed{\rm 1567.44 \approx height}[/tex]

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