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1). A box is ( 2x -3 ) by ( x + 5 ) by ( 3x + 1 ), what is the volume of the box if x = 3 cm?
2). The formula for the area of a triangle is A= bh/2 if the base (b) = 10 cm and the height (h) = 6 cm, what is the area of the triangle?
3). The length (l) of the rectangle is x² + 2x - 3 and the width (w) is 5x + 4, what is the perimeter of the rectangle?
4). From the sum of 3x³ + 7x² - 5 and 2x² + 3x + 8 take away 5x² + x - 5.
5). What should be added to 3x³ + 4x² - 7 to have a sum of 4x³ + x² + 5
answer
1.substitute 3cm to all x
(2(3)-3)x(3+5)x(3(3)+1)

=3x8x10= 240-answer

2. 10x6=60÷2=30cm²-answer

3.x²+2x-2 + 5x+4 = x²+7x+1-answer

4. answer: 3x³+4x²+2x+8

5.x³-3x²+12

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Sagot :

1). A box is ( 2x -3 ) by ( x + 5 ) by ( 3x + 1 ), what is the volume of the box if x = 3 cm?

2). The formula for the area of a triangle is A= bh/2 if the base (b) = 10 cm and the height (h) = 6 cm, what is the area of the triangle?

3). The length (l) of the rectangle is x² + 2x - 3 and the width (w) is 5x + 4, what is the perimeter of the rectangle?

4). From the sum of 3x³ + 7x² - 5 and 2x² + 3x + 8 take away 5x² + x - 5.

5). What should be added to 3x³ + 4x² - 7 to have a sum of 4x³ + x² + 5

answer

1.substitute 3cm to all x

(2(3)-3)x(3+5)x(3(3)+1)

[tex]\huge\red{\boxed{1. \: =3x8x10= 240}}[/tex]

[tex]\red{\boxed{2. \: 10x6=60÷2=30cm²}}[/tex]

[tex]\red{\boxed{3. \: x²+2x-2 + 5x+4 = x²+7x+1}}[/tex]

[tex]\huge\red{\boxed{4. \: 3x³+4x²+2x+8}}[/tex]

[tex]\huge\red{\boxed{5. \: x³-3x²+12}}[/tex]