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1. JP's age is twice the age of Reyna. The sum of their ages does not exceed 51.
2. Twice the sum of a number and 10 is 55.
3. Cut a 60 cm ribbon into two such that one part is one-third of the other.​

Sagot :

Virgolicious25idn

Answer:

1. 17 (age of Reyna), 34 (age of JP)

2. x=17.5

3. 1= 40 cm

2= 20 cm

Explanation:

1. Let

x be the age of Reyna

2x be the age of JP

x + 2x = 51

Solution:

x + 2x = 51

3x/3 = 51/3

x = 17 (age of Reyna)

2x = 2(17) = 34 (age of JP)

Checking:

17+34= 51 ✔️

2. 2(a number + 10)=55

Let

x be the number

Solution:

2(x+ 10)=55

2x + 20=55

2x=55-20 [transpost]

2x=35

2x/2=35/2

x=17.5

Checking:

2(x+ 10)=55

2(17.5+ 10)=55 [substitute the value of x]

2 (27.5)=55

55=55 ✔️

3. Solution:

60 x 1/3= 20 cm

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