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find the value of x if f(x)=6


pleas asap


Sagot :

Answer:

suppose f(x)=6/5-x^3

calculate the exact value of x when f(x)=6

so: 6=6/5-x^3

6=6(5-x^3)

6=30-6x^3

-6x^3=6-30

-6x^3=-24

-6x^3+24=0

6x^3-24=0

6(x^3-4)=0

x^3-4=0

x^3=4

x=cube root 4

x=1.5874

needs to be a fraction form

but x=4/3

Answer:

i dont know the answer

Step-by-step explanation:

sorry