Answer:
The final velocity of the male bungee jumper freely falling at the end of 1.5 seconds is -14.7 m/s.
Explanation:
For a rectilinear motion, one of the formula we use is Vf = Vi + at
where:
Vf is the final velocity
Vi is the initial velocity
a is the acceleration along the horizontal
t is the time
For a free falling body, we change the symbol of acceleration, a to g where g means acceleration due to gravity.
Now, the formula free falling body becomes Vf = Vi + gt.
The acceleration due to gravity has a constant value of 9.8 [tex]\frac{m}{s^{2} }[/tex]. Since the direction of the falling body is downward, the sign for the acceleration due to gravity is said to be negative.
The given data for the problem are the following:
t = 1.5 seconds
g = -9.8 m/s
Vi = 0
The initial velocity is zero because when the bungee jumper has reached the maximum height, his final velocity becomes zero which is his initial velocity in falling down.
Solve for the velocity of the bungee jumper:
Let us use the formula for free falling body:
Vf = Vi + gt
Substitute the given data:
Vf = 0 +(-9.8 [tex]\frac{m}{s^{2} }[/tex])(1.5[tex]s[/tex])
Vf = -14.7 m/s
Therefore, the final velocity is -14.7 m/s.
For more information about free falling body, just click on the following links:
* Recommendations about free falling bodies
https://brainly.ph/question/2162209
* Other example on free falling body
https://brainly.ph/question/2170448
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