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a rectangle has a perimeter of 60. cm with a length of 10 cm and a width of √x-3 cm find the x​

Sagot :

The formula of Perimeter of a Rectangle is 2L + 2W

So, P = 2L + 2W

60 = 2(10) + 2(√x-3)

60 = 20 + 2√x-3

-20 + 60 = 2√x-3

40 = 2√x-3

(Divide both sides by 2)

20 = √x-3

(To get rid of the square root, square both sides)

400 = x-3

3 + 400 = x

403 = x

The value of x is 403.