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Answer:
person stands 150 ft away from a flagpole and measures an angle of elevation of 32∘ from his horizontal line of sight to the top of the flagpole. Assume that the person's eyes are a vertical distance of 6 ft from the ground. What is the height of the flagpole?
Step-by-step explanation:
The picture on the right describes the situation. We see that the height of the flagpole is h+6 ft, where
h150 = tan32∘⇒h = 150tan32∘ = 150(0.6249) = 94 .(1.3.1)
How did we know that tan32∘=0.6249 ? By using a calculator. And since none of the numbers we were given had decimal places, we rounded off the answer for h to the nearest integer. Thus, the height of the flagpole is h+6=94+6=100 ft .