IDNStudy.com, ang iyong gabay para sa maaasahan at mabilis na mga sagot. Tuklasin ang mga kumpletong sagot sa iyong mga tanong mula sa aming komunidad ng mga eksperto.

patulong Naman po Dito please​

Patulong Naman Po Dito Please class=

Sagot :

[tex]1.) \: \sqrt{75} = \sqrt{25} \times \sqrt{3} = 5 \sqrt{ 3} [/tex]

[tex]2.) \: \sqrt[3]{135} = \sqrt[3]{27} \times \sqrt[3]{5} = 3 \sqrt[3]{5} [/tex]

[tex]3.) \: \sqrt{12x^{3} } = \sqrt{4 \times 3 \times x^{2} \times x} = 2x \sqrt{3x} [/tex]

[tex]4.) \: \sqrt{150} = \sqrt{25} \times \sqrt{6} = 5 \sqrt{6} [/tex]

[tex]5.) \: \sqrt{28x^{4}y^{2} } = \sqrt{7 \times 4 \times x^{2} \times x^{2} \times {y}^{2} } = 2x^{2}y \sqrt{7} [/tex]

[tex]6.) \: \frac{ \sqrt{5} }{ \sqrt{6} } = \frac{ \sqrt{5} }{ \sqrt{6} } \times \frac{ \sqrt{6} }{ \sqrt{6} } = \frac{ \sqrt{5 \times 6} }{( \sqrt{6} )^{2} } = \frac{ \sqrt{30} }{6} [/tex]

[tex]7.) \: \frac{ \sqrt{24} }{ \sqrt{15} } = \frac{ \sqrt{24} }{ \sqrt{15} } \times \frac{ \sqrt{15} }{ \sqrt{15} } = \frac{ \sqrt{24 \times 15} }{( \sqrt{15})^{2} } = \frac{ \sqrt{3 \times 2 \times 4 \times 5 \times 3} }{15} = \frac{6 \sqrt{10} }{15} = \frac{2 \sqrt{10} }{5} [/tex]

[tex]8.) \: \frac{ \sqrt{20} }{ \sqrt{28} } = \frac{ \sqrt{20} }{ \sqrt{28} } \times \frac{ \sqrt{28} }{ \sqrt{28} } = \frac{ \sqrt{20 \times 28} }{( \sqrt{28})^{2} } = \frac{ \sqrt{5 \times 4 \times 7 \times 4} }{20} = \frac{4 \sqrt{35} }{20} = \frac{ \sqrt{35} }{5} [/tex]

[tex]9.) \: \frac{1}{ \sqrt{12} } = \frac{1}{ \sqrt{12} } \times \frac{ \sqrt{12} }{ \sqrt{12} } = \frac{ \sqrt{12} }{( \sqrt{12}) ^{2} } = \frac{ \sqrt{12} }{12} [/tex]

[tex]10.) \: \sqrt{ \frac{1}{3} } = \frac{ \sqrt{1} }{ \sqrt{3} } = \frac{ \sqrt{1} }{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{ \sqrt{3 \times 1} }{( \sqrt{3})^{2} } = \frac{ \sqrt{3} }{3} [/tex]