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B. Solve the given problem.
1. The area of a rectangle measures 25x⁵y⁷. The length of the rectangle measures
5x²y3. What is the width of the rectangle?
Questions:
-What concepts have you applied?
-How did you solve the given problem?


B Solve The Given Problem1 The Area Of A Rectangle Measures 25xy The Length Of The Rectangle Measures5xy3 What Is The Width Of The RectangleQuestionsWhat Concep class=

Sagot :

Answer:

- I applied the formula for a rectangle width and the dividing of two measures.

- I solved the given problem by dividing the area and length, giving the answer of [tex]5 {x}^3 {y}^4[/tex] as the width of the rectangle.

Step-by-step explanation:

To solve for the width of a rectangle, use the formula [tex]W=\frac{A}{L}[/tex]. In our case, solve using the following:

[tex]W=\frac{A}{L} \\ W=\frac{25 {x}^{5} {y}^{7} }{5 {x}^{2} {y}^{3} } \\ W=\frac{25 {x}^{3} {y}^{4} }{5} \\ W=5 {x}^3 {y}^{4} [/tex].

In the end, our width is [tex]5 {x}^{3} {y}^4 [/tex].