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3. Using the Babylonian procedures, solve each of these systems:
a. x - y = 6, xy = 16
b. x - y = 4, xy = 21
c. x + y = 8, xy 15​


Sagot :

Answer:

a.) x = 8, y = 2

b.) x = 7, y = 3

c.) x = 5, y = 3

Step-by-step explanation:

a. x - y =6, xy = 16

Let x = 3 + z , y = -3 + z

x+y = 3 + z - (-3 + z)

= 3 + 3 + z - z

= 6

Then xy = (3 + z)(-3+z) = 16

= -9 + z^2 = 16

-9+9 + z^2 = 16+9

z^2 = 25

z = √z^2

z = √25

z = 5

x = 3 + 5

= 8

y = -3 + 5

= 2

xy = 16

(8)(2) = 16

b. x - y = 4, xy = 21

Let x = 2 + z, -2 + z

x + y = 2 + z - (-2 + z)

= 2 + 2 + z - z

= 4

Then xy = (2 + z)(-2 + z) = 21

= -4 + z^2 = 21

-4+4 + z^2 = 21+4

z^2 = 25

z = √z^2

z = √25

z = 5

x = 2 + 5

= 7

y = -2 + 5

= 3

xy = 21

(7)(3) = 21

c. x + y = 8, xy = 15

Let x = 4 + z,y = 4 - z

xy = (4 + z)(4 - z) = 15

16 - z^2 = 15

16-15 - z^2 = 15-15

1 - z^2 = 0

1 - z^2 + z^2 = 0 + z^2

z^2 = 1

z = √z^2

z = 1

x = 4 + 1

= 5

y = 4 - 1

= 3

xy = 15

(5)(3) = 15

#Carry on Learning

LeakHelps

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ThankYou ^_^