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Sagot :
The numbers are 12, 38 and 50.
the second number is = 2+3a
the third is = a+b
I just used the Trial and Error strategy.
I started with 10, then 11 and so on until I found the answer.
the second number is = 2+3a
the third is = a+b
I just used the Trial and Error strategy.
I started with 10, then 11 and so on until I found the answer.
let x= the 1st number
y=2nd number
z=3rd number
equations: x + y + z = 100 -----> eq.1
y = 2 + 3x -------> eq.2
z = x + y ---------> eq.3
substitute eq. 2 to eq.3 : z= x + 2 + 3x
z= 2 + 4x -----> eq.4
substitute eq. 2 and eq. 4 to eq.1 : x + 2 + 3x + 2 + 4x= 100
8x + 4= 100
x = 12
substitute the value of x to eq. 2: y= 2 + 3(12)
y= 38
substitute the value of x and y to eq. 3: z = 12 + 38
z = 50
the numbers are 12, 38 and 50.
y=2nd number
z=3rd number
equations: x + y + z = 100 -----> eq.1
y = 2 + 3x -------> eq.2
z = x + y ---------> eq.3
substitute eq. 2 to eq.3 : z= x + 2 + 3x
z= 2 + 4x -----> eq.4
substitute eq. 2 and eq. 4 to eq.1 : x + 2 + 3x + 2 + 4x= 100
8x + 4= 100
x = 12
substitute the value of x to eq. 2: y= 2 + 3(12)
y= 38
substitute the value of x and y to eq. 3: z = 12 + 38
z = 50
the numbers are 12, 38 and 50.
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