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2 (10/15) + 5 (-2x+1) =1

how will i solve this?

Sagot :

Dominiidn
[tex]2(\frac{10}{15})+5(-2x+1)=1 \\ \\ \frac{2}{1}( \frac{10}{15})-10x+5 \\ \\ \frac{20}{15}-10x=1-5 \\ \\ \frac{20}{15}-10x=-4 \\ \\ \frac{4}{3}-10x=-4 \\ \\ (3)( \frac{4}{3}-10x=-4) \\ \\ 4-30x=-12 \\ \\ -30x=-12-4 \\ \\ \frac{-30x}{-30}= \frac{-16}{-30}\to\boxed{x= \frac{8}{15}} \\ \\ Hope\ it\ Helps:) \\ Domini [/tex]
Jeremiaidn
Do the distributive property of multicplication.

2(10/15) + 5(-2x+1)=1
2(2/3) + 5(-2x) + 5(1)=1
4/3 + -10x+5=1
Multiply the terms by 3, the denominator to make 4/3 a whole number.

3(4/3 + -10x + 5 = 1
4 + -30x +15 = 3
-30x +19=3
-30x =3-19
-30x = -16
-30x/-1 = -16/-1
30x=16
30/30x=16/30
x=8/15