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an 8-hour river cruise goes 12km upstream and then back. The speed of the river current is 2kph. What is the speed of the boat in still water?​

Sagot :

Answer:

4kph

Step-by-step explanation:

Let x be the speed of the boat

Speed of the river  = 2 kph

Total time spent = 8 hours

Distance = 12 km

Speed of the boat upstream ( against the river current) = x - 2

Speed of the boat downstream ( along with the current ) = x +2

The formula for t =  d/s

Where

d is distance

s is speed

Therefore the working equation would be

time for downstream + time for upstream = 8 hours

[tex]\frac{12}{x+2} + \frac{12}{x-2} = 8[/tex]

Multiplying both sides (x+2)(x-2) by  for the purpose of eliminating fractions

[tex]\frac{12(x+2)(x-2)}{x+2} + \frac{12(x+2)(x-2)}{x-2} = 8(x+2)(x-2)\\[/tex]

Cancel same terms

12(x-2) + 12(x+2) = 8(x+2)(x-2)

Solving further

[tex]12x-24+12x+24 = 8x^2 - 32[/tex]

[tex]24 x = 8x^2 - 32\\8x^2 -24x- 32 = 0\\x^2 - 3x -4 = 0\\\\\text {Factoring}\\(x-4)(x+1) = 0[/tex]

Finding the roots

x-4 = 0

x = 4

x+1 = 0

x = -1

Disregarding the negative value of x ,

The answer therefore is 4 kph for the speed of the boat in still water

Checking

[tex]\frac{12}{4+2} + \frac{12}{4-2} = 8\\2+6 =8\\8 =8[/tex]

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