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Find the equation of a line in standard form if it passes through (3/4, -2) and has a slope of 1/2

Y-y1 = m (x-x1)
Yan formula

Sagot :

y-y1=m(x-x1)
2[y+2=1/2(x-3/4)]
4[2y+4=x-3/4]
8y+16=4x-3
-1[8y-4x=-19]
4x-8y=19

Hope this helps =)

[tex] Hope\ you'll\ understand\ this... \\ I\ solve\ this\ with\ care:) \\ \\ y-y1=m(x-x1) \\ \\ 2[y+2= \frac{1}{2}(x- \frac{3}{4})] \\ \\ 4[2y+4=x- \frac{3}{4}] \\ \\ 8y+16=4x-3 \\ \\ -1[8y+4x=-19] \to \boxed{ 4x-8y=19} \\ \\ Hope\ it\ helps:) \\ Domini[/tex]