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Find the equation of a line in standard form if x-intercept is -5/7 and y-intercept is 2 1/4
Eto formula:
X/a + y/b =1

Sagot :

x/(-5/7)+y/(2 1/4)=1
Change to improper fraction:
2 1/4=9/4

[x/(-5/7)+y/(9/4)=1](-5/7)(9/4)
x+y=-45/28

Hope this helps =)



[tex] \frac{x}{a} + \frac{y}{b} = 1[/tex]
Having a and b as -5/7 and 2 1/4 respectively, plugging in you'll have:
[tex] \frac{x}{-5/7} + \frac{y}{2 1/4} = 1[/tex]
Changing 2 1/4 to improper fraction you'll have
[(2*4)+1]/4 = 9/4
[tex] \frac{x}{-5/7} + \frac{y}{9/4} = 1 [/tex]
This can be expressed as
[tex] \frac{-7x}{5} + \frac{4y}{9} = 1 [/tex]
Get the LCD
[tex] \frac{-7x(9) + 4y(5)}{45} = 1[/tex]
Cross multiply 45
[tex]-63x + 20y = 45[/tex]
Standard equation of a line is 
Ax + By = C
Transposing -63x +20y to the right and 45 to the left
[tex]-45 = 63x - 20y[/tex]
or
[tex]63x - 20y = -45[/tex]