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(2x+1) (3x-1)
Special product

Sagot :

[tex](2x+1)(3x-1) \\ \\ Use \ FOIL \ Method \ to \ solve \ this \ problem; \\ \\ First;2x \times3x=6 x^{2} \\ Outer;2x\times-1=-2x \\ Inner;1\times3x=3x \\ Last;1\times-1=-1 \\ \\ 6 x^{2} -2x+3x-1 \\ \\ \boxed{6 x^{2} +x-1} \\ \\ Hope \ this \ Helps:) \\ Domini[/tex]
FOIL method

First: 2x * 3x = 6x²
Outer:  2x * -1 = -2x
Inner: 1 * 3x = 3x
Last: 1 * -1 = -1

Add all but Subtract -2x and 3x since they have the same variable

Therefore;

6x² + x - 1

I hope it helps