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cita is six years older than bona,and bona is twice as old as albert.four years from now,cita age will be 8 years less than the sum of albert and bona age.how old is each now
Let 'x' be the age of Cita at present 'y' be the age of Bona at present 'z' be the age of Albert at present ------------------------------------------------ Four years from now: x+4 ---Cita's age y+4 ---Bona's age z+4 ---Albert's age ------------------------------------------------- Translating the statements into mathematical expressions you'll have: x = y + 6 ----equation 1 y = 2z ----equation 2 (x+4) = (y+4) +(z+4) - 8 -----equation 3 From equation 3 (x+4) = (y+4) +(z+4) - 8 x + 4 = y + 4 + z + 4 - 8 x + 4 = y + z -----equation 3' Express x and z in terms of y From equation 2 y = 2z z = y/2 ----equation 2' Substitute equations 2' and equation 1 to equation 3' x + 4 = y + z (y+6) + 4 = y + y/2 y + 6 + 4 = y + y/2 Combine like terms y - y + y/2 = 10 y/2 = 10 Cross multiply y = 20 yrs old ----Bona's age Substitute y=20 to equation 2 y = 2z 20 = 2z z = 20/2 z = 10 ----Albert's age substitute y=20 to equation 1 x = y + 6 x = 20 + 6 x = 26 yrs old ---Cita's age
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