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There are 6 books on a reading list. Students must read 3 of the books on the list. In how many different ways can a student select 3 books?

Sagot :

This problem involves combination.
Using the formula for combination as:
[tex]_nC_r = \frac{n!}{(n-r)!r!} [/tex]
n=6
r=3
[tex]_6C_3 = \frac{6!}{(6-3)!3!} [/tex]
[tex]_6C_3 = \frac{6(5)(4)(3)(2)(1)}{(3(2)(1))(3(2)(1))} [/tex]
[tex]_6C_3 = 20[/tex]
therefore there are 20 ways to which a student can select 3 books.