Hello !!
The first multiple is 0 , the next term is the result of the sum of current term with 3. So , we have.
An = A1 + (n - 1) × d
A14 = 0 + (14 - 1) × 3
A14 = 0 + 13 × 3
A14 = 0 + 39
A14 = 39
Every multiples of 3.
M(3) = 0 , 3 , 6 , 9 , 12 , 15 , 18 , 21 , 24 , 27 , 30 , 33 , 36 , 39 ...
Final result : 39 is the 14th multiple on table 3.
I hope I have collaborated !
