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Sagot :
i think we will solve for x.
so 2(cube root of 1-3x)=-4
we will cube both side
so the radical will now cancel
8(1-3x)/8=-64/8
1-3x=-8
so "x=3" then if we substitute the value of x from the given equation we will get -4
so 2(cube root of 1-3x)=-4
we will cube both side
so the radical will now cancel
8(1-3x)/8=-64/8
1-3x=-8
so "x=3" then if we substitute the value of x from the given equation we will get -4
2∛1-3x = -4 Divide both side by 2
∛1-3x = -2 to cancel the radical raise both side by 3
the equation will be,
1-3x= -8
transpose 1 to the right
-3x=-9 divide the equation by-3
x=3
∛1-3x = -2 to cancel the radical raise both side by 3
the equation will be,
1-3x= -8
transpose 1 to the right
-3x=-9 divide the equation by-3
x=3
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