let 'x' be the length of one leg
'x + 2' be the length of the other leg
remember that it is a right triangle then we may use pythagorean theorem
c² = a² + b²
where c is the hypotenuse and a & b are the legs
10² = x² + (x + 2)²
100 = x² + x² + 4x + 4
2x² + 4x +4 - 100 = 0
2x² + 4x - 96 = 0
dividing the whole equation with 2
x² + 2x - 48 = 0
(x+8)(x-6) = 0
x = -8, x = 6
taking the positive values you'll have:
a = 6, b =8
