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*molar mass*
 what is the mass of 5.76x10expo 22 molecules anmonia (nh3)?

Sagot :

first you need to know the number of moles of [tex]5.76 x 10 x^{22} [/tex] by divding it to avogadro's number ([tex]6.022x10 x^{23} [/tex])

[tex]5.76 x 10^{22} molecules x \frac{1mole}{6.022 x 10^{23}molecules } [/tex]
= 0.09 mole

find the molar mass of ammonia
N + 3H = molar mass of ammonia
(14.01) + (3)(1.008) = 17.034 g/mol

now, multiply 0.09 mole to 17.034 g/mol

[tex]0.09 mole NH_{3} x \frac{17.034grams}{1 mole NH_{3} } [/tex]
= 1.53306 grams