Euricahacostaidn
Answered

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Phyllis invested $12,000, a portion earning a simple interest rate of 4 1/2% per year and the rest earning a rate of 4% per year.After 1 year the total interest earned on these investments was $525.How much money did she invest at each rate ?

Sagot :

Shinalcantaraidn
let 'x' be the amount invested at 4.5%
    'y' be the amount invested at 4%
Since you are provided that the total investments earned 525 then you'll have the equation as:
 0.045x + 0.04y = 525   -----equation 1
You're given the total amount of 12,000 then
 x + y = 12,000     -------equation 2
transposing x to the right side for equation 2
 y = 12,000 - x   ---------equation 3
substitute equation 3 to equation 1
 0.045x + 0.04y = 525
 0.045x + 0.04(12,000-x) = 525
 0.045x + 480 - 0.04x = 525
 0.045x - 0.04x = 525 - 480
0.005x = 45
       x = 9,000
substitute the value of 'x' to equation 3
 y = 12,000 - x 
 y = 12,000 - 9,000
 y = 3,000
JamMantalabaidn
Let  x be the amount invested at 4.5%.
    y be the amount invested at 4%.

Since you are provided that the total investments earned 525, then you'll have the equation as:
 0.045x + 0.04y = 525  
Total amount of 12,000 then:
 x + y = 12,000    
Transpose x to the right side:
 y = 12,000 - x  
Substitute equation 3 to equation 1
 0.045x + 0.04y = 525
 0.045x + 0.04(12,000-x) = 525
 0.045x + 480 - 0.04x = 525
 0.045x - 0.04x = 525 - 480
0.005x = 45
       x = 9,000
Substitute the value of x to equation 3:
 y = 12,000 - x 
 y = 12,000 - 9,000
 y = 3,000
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