the radius is equal to 25 m stated in the drawing
by cosine law
angle O = arccos( 25^2 + 25^2 - 36^2)/ 2(25)(25) = 92.11 degree
solving angle T
we need angle B & A
angle A=angle B = arccos( 25^2 + 36^2 - 25^2)/ 2(36)(25) = 43.95 degree
for the another triangle
since the tangent line is 90 degree to the radius
90 - 43.95 = 46.05 degree = angle A & B on the another triangle
for angle T
angle T + angle A + angle B = 180
angle T = 180 - 46.05 + 46.05 = 87.9 degree