let x=the amount of tea @6.50
y=the amount of tea @4.25
20(5.6)=the total amount of the blended tea
6.50(x) + 4.25(y) = 20(5.6)
6.5x + 4.25y = 112 ---equation 1
you're given that when the two grade of tea is added you'll have total weight of 20lbs
x+y = 20 -----eq'n 2
from eqn 2:
x = 20 - y ----eq'n 3
substitute eqn 3 to eqn 1
6.50(20-y) + 4.25y =112
130 - 6.5y + 4.25y = 112
-2.25y = -18
y = 8 pounds
substitute y=8 to eq'n 3
x = 20 - 8
x = 12 pounds