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divide 94 into two parts such that the larger is ten more than the twice the smaller

Sagot :

Havingtroublesidn
Let x be the smaller value.
2x+10 is the larger value.

Adding the two to form an equation, we have:
x+2x+10=94

Combining like terms and transposing the constants to the right hand side,
3x=84

Dividing both sides by 3, we get:
x=28.

Therefore, the smaller value is 28.

But, we still have to get the larger value.
Substituting x by 28 on the equation of the larger value, we get:
2(28)+10=66

Therefore the two values are 28 and 66.

Checking:
28+66=94