[tex]\begin{cases} 2x+3y=12\ \ | \ multiply\ both\ sides\ by\ (-2 ) \\ 4x-3y=6 \end{cases} \\\\ \begin{cases} -4x-6y=-24 \\ 4x-3y=6 \end{cases}\\ + -------\\-9y=-18\ \ | \ divide \ both \ sides\ by\ (-9)\\\\\frac{-9}{-9}y=\frac{-18}{-2} \\y=2 [/tex]
[tex]2x+ 3\cdot 2=12\\\\2x+6=12 \ \ |\ subtract\ 6\ to\ both\ sides \\ 2x+6-6=12-6\\2x=6 \ \ | \ divide \ both \ sides\ by\ 2 \\x=\frac{6}{2} \\x=3 \\\\Answer : \ \begin{cases} x=3 \\y=2 \end{cases} [/tex]
