x = distance, t = time, v= initial velocity, a = acceleration;
Assuming the cat is at rest before the fall;
A. x = vt - (1/2)at^2; x = (0 m/s)(2 s) - (1/2)(9.8 m/s^2)(2 s)^2; x = - 19.6 m (ignore the negative sign. It just means that the cat fell downwards);
B. V = Initial Velocity + at; V = (0 m/s) + (-9.8 m/s^2)(2 s); V = -19.6 m/s;
C. Ave. Speed = (V - Initial Velocity); Ave. Speed = 19.6 m/s - 0 m/s; Ave. Speed = 19.6 m/s
