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given are the following forces: A=300N, N 45° E B= 200N, 35° S OF W C= 500N, 60° N OF E D= 400N, 37° W OF N
find the magnitude and direction of the resultant force using: a.) polygon method(graphical method) b.) rectangular - component method (analytical method)
Rectangular
Get the x and y components of each force
A: 300cos45 (x-component) and 300sin45 (y-component)
B: 200cos(180+35) (x-component) and 200sin(180+35) (y-component)
*I added 180 degrees to 35 degrees since the direction is in South of West (3rd quadrant)
C: 500cos60 (x-component) and 500sin60 (y-component)
D: 400cos(90+37) (x-component) and 400cos(90+37) (y-component)
*we add the x-components and y-components to get the components of the resultant force
X-component: 57.576
Y-component: 289.70
R = sqrt (x^2 + y^2)
R = 295.37
To find the direction
tan theta = (289.70/57.576)
theta = 78°45'33.5"
295.37 N, 78.76° E of N
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