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find the equation of the parabola with vertex on line y=x+2, axis of parabola is parallel to the y-axis passing through the point (-3,-1) and the length of the latus rectum is 6 units

Sagot :

Mgis091498idn
If you tried to check, the point (-3,-1) passes through the line y=x+2 meaning the vertex is exactly in the point (-3,-1)

The length of the latus rectum is 6 units meaning    4p=6

Since you said that the parabola is parallel to the y-axis, the equation will look something like this: (x-h)^2=4p(y-k)

so if you try to input all the given you'll get this:

(x+3)^2=6(y+1)

although i'm not so sure since it wasn't mentioned if its facing upward or downward

:)
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