Suriin ang malawak na saklaw ng mga paksa at makakuha ng mga sagot sa IDNStudy.com. Magtanong ng anumang bagay at makatanggap ng mga maalam na sagot mula sa aming komunidad ng mga propesyonal.

ections: Read each problem and then solve. Write your answer on a separate
et
of paper.
Two dice are rolled twelve times and the total number of dots are added up
e are the outcomes of the sum:
Outcomes
(Sum)
mes 47129824653 10 7
1. What is the experimental probability that the sum is greater than 5?
2. What is the experimental probability that the faces with 5 and 6 dots
appear?
3. What is the experimental probability that the sum is an even number?
4. What is the experimental probability that the sum is an odd number?
5. What is the experimental probability that the sum is 4?
vity 2:
ions: Read each problem and then solve. Follow the steps. Write
your

Sagot :

Answer:

1. The total number of times two dice are rolled is 12 x 2 = 24 rolls.

The outcomes where the sum is greater than 5 are:

6 (4+2, 5+1, 6+0), 7 (5+2, 6+1), 8 (6+2, 5+3), 9 (6+3), 10 (6+4, 5+5), 11 (6+5), 12 (6+6).

There are 14 outcomes where the sum is greater than 5.

Experimental probability = Number of favorable outcomes / Total number of outcomes

Experimental probability = 14 / 24

Experimental probability = 7 / 12

2. The outcomes where faces with 5 and 6 dots appear are:

5+6, 6+5

There are 2 outcomes where faces with 5 and 6 dots appear.

Experimental probability = Number of favorable outcomes / Total number of outcomes

Experimental probability = 2 / 24

Experimental probability = 1 / 12

3. The outcomes where the sum is an even number are:

4 (2+2), 6 (3+3, 4+2, 2+4), 8 (4+4, 5+3, 3+5, 6+2, 2+6), 10 (5+5, 6+4, 4+6), 12 (6+6).

There are 11 outcomes where the sum is an even number.

Experimental probability = Number of favorable outcomes / Total number of outcomes

Experimental probability = 11 / 24

4. The outcomes where the sum is an odd number are:

3 (1+2, 2+1), 5 (1+4, 4+1, 2+3, 3+2), 7 (1+6, 6+1, 2+5, 5+2, 3+4, 4+3), 9 (6+3, 3+6, 5+4, 4+5), 11 (6+5, 5+6).

There are 13 outcomes where the sum is an odd number.

Experimental probability = Number of favorable outcomes / Total number of outcomes

Experimental probability = 13 / 24

5. The outcomes where the sum is 4 are:

1+3, 2+2, 3+1

There are 3 outcomes where the sum is 4.

Experimental probability = Number of favorable outcomes / Total number of outcomes

Experimental probability = 3 / 24

Experimental probability = 1 / 8