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1. (3x ^ 2 + 6x)/(3x) =

2. 5x ^ 2 + 10x ^ 3

3.6X4-14x

4.7 39-1846

5.) 3a²+69-9

with solution plss​

Sagot :

1. The given expression is:

(3x^2 + 6x)/(3x)

We can simplify this expression by factoring out the common term (3x):

(3x^2 + 6x)/(3x) = 3x(x + 2)/(3x) = x + 2

So, the answer is x + 2.

2. The given expression is:

5x^2 + 10x^3

This is a polynomial with coefficients of x^2 and x^3. To add these terms, we can use the formula for the sum of a geometric series:

Sum = a(r - 1)/(r - 1) = a(n - 1)/(n - 1)

Here, a = 5, r = 3, and n = 2, so we have:

Sum = 5(2 - 1)/(3 - 1) = 5(1)/2 = 5/2

Similarly, for the x^3 terms:

Sum = 10(2 - 1)/(3 - 1) = 10(1)/2 = 5

So, the total of the x^2 and x^3 terms is 5/2 + 5 = 10/2 + 5 = 15/2. Therefore, the answer is 15/2.

3. The given expression is:

6X4-14x

We can factor out the common term X from the first two terms:

6X4-14x = X(6X3 - 14) = X(6X3 - 14)

Now, we need to find the factors of 6X3 - 14. We can try different integer values for X until we find a pair of factors that multiply to -14 and add up to 6X3.

Let's try X = 2:

6(2)(2) - 14 = 24 - 14 = 10

The factors of 10 are 1 and 10, or 2 and 5. Since we already have the factor of 2, we will use 5