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The solution for x are $x = \pm 4\sqrt{2}$ or $ x = \: 4\sqrt{2} $ and $ x = - \: 4\sqrt{2} $
Solution:
To extract the square root of the equation $ {x}^{2} = 32 $, follow these steps:
Step 1: Understand the Equation
Step 2: Take the Square Root
[tex] \sqrt{ {x}^{2} } = \sqrt{32} [/tex]
Step 3: Simplify the Square Root
[tex]\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2}[/tex]
Thus, the solutions for x are:
[tex]x = \pm \: 4 \sqrt{2} [/tex]
This means that $ x $ can be either $ 4\sqrt{2} $ or $ -4\sqrt{2} $.