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2x²-8x+9 what is the factor​

Sagot :

Answer:

To factor the quadratic expression

[tex]2x² - 8x + 9[/tex]

we need to find two numbers that multiply to

[tex](2 \times 9 = 18) and \: add \: up \: to \: (-8).[/tex]

The factors of 18 are:

[tex](1 \times 18), (2 \times 9), and (3 \times 6).[/tex]

If you need to solve it, you can use the quadratic formula:

[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

For the quadratic equation 2x² - 8x + 9 = 0:

  • a = 2
  • b = -8
  • c = 9

[tex]x = \frac{-(-8) \pm \sqrt{(-8)^2 - 4 \cdot 2 \cdot 9}}{2 \cdot 2}[/tex]

[tex]x = \frac{8 \pm \sqrt{64 - 72}}{4}[/tex]

[tex]x = \frac{8 \pm \sqrt{-8}}{4}[/tex]