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Determine the vertex of the parabola:

2x^2 - 36x + 164

Sagot :

Answer:

(9,1)

Step-by-step explanation:

I am assuming this is y = 2x² - 36x + 164

Let's solve it in two ways.

a. STANDARD FORM

The standard form of a function is y = ax² + bx + c and look, our problem is already in this form so we can now use the formula, -b/2a, to find the x coordinate (x = -b/2a is also the formula for the axis of symmetry). a = 2 b = -36

  • x = -(-36) / 2(2)
  • x = 36/4
  • x = 9

Now, let's go ahead and substitute this value of x to the original equation.

  • y = 2(9)² - 36(9) + 164
  • y = 162 - 325 + 164
  • y = 1

So, combining our values together into a coordinate, we'll have (9,1).

b. VERTEX FORM

For this one, we'll transform the equation a bit to turn it into its vertex form, that is, y = a(x - h)² + k, and from that we'll have our coordinate for the vertex which is (h,k).

y = 2x² - 36x + 164 » y = 2(x - 9)² + 1

This means that h = 9 and k = 1 so our vertex will be at (9,1).