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Sagot :
[tex]\sf\pink{. . • ☆ . ° .• °:. *₊ ° . ☆. . • ☆ . ° .• °:. *₊ ° . ☆}[/tex]
[tex]\pink{\mathbb{\huge{꧁ᬊᬁ~ANSWER~ᬊ᭄꧂}}}[/tex]
[tex]\rm{\pink{Justification:}}[/tex]
[tex]\sf\pink{ᯓ★}[/tex] The given information states that circle B is internally tangent to circle A at point P, and circle C is internally tangent to circle D at point P. This means that the points of tangency are the same point, P.
[tex]\sf\pink{ᯓ★}[/tex] The segment addition postulate states that if a point lies between two other points on a line segment, then the length of the entire segment is equal to the sum of the lengths of the two parts.
[tex]\sf\pink{╴╴╴╴╴⊹ꮺ˚ ╴╴╴╴╴⊹˚ ╴╴╴╴˚ೃ ╴╴}[/tex]
[tex]\sf\pink{ᯓ★}[/tex] Using the segment addition postulate, we have:
- BD = BC + CD
- AC = AB + BC
[tex]\sf\pink{ᯓ★}[/tex] Substituting the given values:
- BD = AC (given)
- AB = 4 (given)
- SD = 2 (given)
[tex]\sf\pink{ᯓ★}[/tex] Solving for BC:
- BD = BC + CD
- AC = AB + BC
- 4 = 4 + BC
- BC = 0
[tex]\sf\pink{ᯓ★}[/tex] Since BC = 0, the diameter of circle C is equal to the chord AC, which is 4.
[tex]\sf\pink{ᯓ★}[/tex] Again using the segment addition postulate:
- BD = BC + CD
- 2 = 0 + CD
- CD = 2
[tex]\sf\pink{ᯓ★}[/tex] The diameter of circle D is twice the length of CD, which is the radius of circle D.
- Diameter of circle D = 2 × CD = 2 × 2 = 4
[tex]\sf\pink{╴╴╴╴╴⊹ꮺ˚ ╴╴╴╴╴⊹˚ ╴╴╴╴˚ೃ ╴╴}[/tex]
Therefore, the length of the diameter for circle C is [tex]\blue{\underline{\sf\pink{4}}}[/tex], and the length of the diameter for circle D is also [tex]\blue{\underline{\sf\pink{4}}}[/tex].
[tex]\bold{\small\pink{⋆˚࿔~ ashrieIIe~˚⋆}}[/tex] [tex]\pink{\heartsuit}[/tex]
[tex]\sf\pink{. . • ☆ . ° .• °:. *₊ ° . ☆. . • ☆ . ° .• °:. *₊ ° . ☆}[/tex]
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