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A balloon containing 0.500 mol Ar at 0.00°C and 65.0 kPa pressure is expanded by adding more argon. Formula: PV = nRT (R = 8.317 L•kPa/mol•K) What is the original volume of the gas?

Sagot :

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[tex]\mathbb{\huge\red{ANSWER}}[/tex]

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[tex]\bold{\red{GIVEN}}[/tex]

  • n = 0.500 mol of Ar
  • T = 0.00°C = 273.15 K
  • P = 65.0 kPa
  • R = 8.317 L·kPa/mol·K

[tex]\bold{\red{REARRANGE}}[/tex]

  • V = (nRT) / P
  • V = (0.500 mol × 8.317 L·kPa/mol·K × 273.15 K) / 65.0 kPa
  • V = 5.52 L

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[tex]\boxed{\sf\green{✓}}[/tex] Therefore, the original volume of the gas in the balloon was [tex]\underline{\red{5.52~ L}}[/tex].

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