IDNStudy.com, ang iyong destinasyon para sa malinaw at mabilis na mga sagot. Sumali sa aming komunidad ng mga bihasa upang makahanap ng mga sagot na kailangan mo sa anumang paksa o problema.

A 15kg rectangular block with a length of 70cm and a width of 40cm rest on a table that pressure does the book exert on the table

Sagot :

SOLUTION

To determine the pressure exerted by the block on the table, we can use the formula for pressure, which is:

  • Pressure = Force / Area

In this case, the force exerted by the block on the table is its weight, which can be calculated using the formula:

  • Force = mass x gravity

Where:

  • mass = 15 kg
  • gravity = 9.8 m/s^2 (the acceleration due to gravity)
  • Force = 15 kg x 9.8 m/s^2 = 147 N

The area of the block's surface that is in contact with the table is the area of the rectangle, which can be calculated using the formula:

  • Area = length x width

Where:

  • length = cm = 0.7 m
  • width = 40 cm = 0.4 m
  • Area = 0.7 m x 0.4 m = 0.28 m^2

Now, we can plug in the values we've calculated into the pressure formula:

  • Pressure = Force / Area
  • Pressure = 147 N / 0.28 m^2 =.29 Pa

Therefore, the pressure exerted by the block on the table is 519.29 Pascals.

Explanation:

To calculate the pressure exerted by the rectangular block on the table, we can use the formula for pressure:

Pressure = Force / Area

Given:

- Weight of the block = 15 kg

- Length of the block = 70 cm = 0.7 m

- Width of the block = 40 cm = 0.4 m

First, we need to find the force exerted by the block, which is equal to its weight:

Force = Mass * Acceleration due to gravity

Force = 15 kg * 9.81 m/s² (standard acceleration due to gravity)

Force = 147.15 N

Next, we need to calculate the area of contact between the block and the table, which is the product of the length and width of the block:

Area = Length * Width

Area = 0.7 m * 0.4 m

Area = 0.28 m²

Now, we can calculate the pressure exerted by the block on the table:

Pressure = Force / Area

Pressure = 147.15 N / 0.28 m²

Pressure ≈ 525.54 Pa

Therefore, the block exerts a pressure of approximately 525.54 Pascal on the table.