Rainxxxidn
Answered

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2x^2-3x-2=0 (completing the square)

Sagot :

Raquelidn
2x^2-3x-2=0

1/2[2x^2-3x-2=0]1/2

x^2-3/2x-1=0

x^2-3/2x=1

x^2-3/2x+[1/2(-3/2)]^2=1+[1/2(-3/2)]^2

x^2-3/2x-81/16=1-81/16

x^2-3/2X-81/16=-64

(x-9/4)(x-9/4)=-64

sqrt of (x-9/4)=+-sqrt of (-64)

x-9/4=+-sqrt of -64

for the x1
x=9/4+sqrt of -64

for the x2
x=9/4-sqrt of -64

i hope it will help you
^_^