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Direction: Study the illustration and answer the following questions. A. A boy threw a ball straight up in the air with an initial velocity of 50 m/s. It reached its maximum height after 5 seconds. g = -9.8 m/s² V p = 0 00 v₁ = 50 m/s t = 5s Source of image

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Answer:

The velocity of the ball when it left the boy`s hand is 39.4 m/s.

Explanation:

Given time taken by ball to reach the maximum height, t = 4 s.

To calculate the initial velocity of the ball when it left the boy`s hand, use first equation of motion,

v = u +gt

Here, v is initial velocity u is final velocity t is the time taken and g is acceleration due to gravity and its value is

At maximum height the final velocity of the ball, v =0.

Substitute the given values in above equation we get,

Thus, the velocity of the ball when it left the boy`s hand is 39.4 m/s.

Explanation:

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