First, we need to find their volumes.
V = πr²h
V = (3.14)(10 cm)²(8 cm)
V = (3.14)(100 cm²)(8 cm)
V = 2512 cm³ - First milk
Using the same formula...
V = πr²h
V = (3.14)(8 cm)²(10 cm)
V = (3.14)(64 cm²)(10 cm)
V = 2009.6 cm³ - Second milk
Then subtract.
2512 cm³ - 2009.6 cm³ = 502.4 cm³
Therefore, the first milk is can hold 502.4 cm³ more milk than the smaller one.