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60% of the circumference of a circle is cut to form a rectangle with it's length being 3 times it's width. The dimeter of the circle is 42cm.find the width of a rectangle.( use π = 22\7)what is the answer?
First things we do is to find the Circumference of a circle using the formula C = 2π(d/2) where, C is the circumference and d = diameter of the circle we will use π=22/7 and d = 42 cm C = 2(22/7)(42/2) C = 2(22/7)(21) C = (2)(22)(3) C = 132
There are 60% of the circumference of a circle that is cut to form a rectangle. We will get that 60% by multiplying it to the circumference to get the Perimeter of the rectangle. P = (0.60)(132) P = 79.2
Perimeter of the rectangle is P = 2L + 2W, where P is the perimeter, L is the length, and W is the width
Since, length is 3 times its width, we will denote this as L = 3W
So we have P = 2L + 2W 79.2 = 2(3W) + 2W 79.2 = 6W + 2W 79.2 = 8W 79.2 / 8 = 8W / 8 9.9 = W W = 9.9 cm
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