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If eight boys are to occupy eight seats at a circular table, how many different arrangements are possible?

Sagot :

the answer I think would be is 8..
The formula for circular permutation is P = (n-1)!

Therefore,

P = (8-1)!
   = 7!
   =  7 * 6 * 5 * 4 * 3 * 2 * 1
   = 5,040

5,040 different arrangements are possible.