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Out of 5200 households surveyed, 2107 had a dog, 807 had a cat, and 303 had both dog and a cat. What is the probability that a randomly selected household has a dog or cat?

Sagot :

Earlyjeandandap155feidn

Given:

Households with a Dog = 2107

Households with a Cat = 807

Households with both dog and cat = 303

Solution: This is not mutually exclusive events, in other words the probability that either A or B occurs is the sum of their probabilities decreased by the probability of both occurring.

Probability (Dog or Cat) = Probability (Dog) + Probability (Cat) – Probability (both dog and cat)

= [tex] \frac{2107}{5200} + \frac{870}{5200} - \frac{303}{5200} [/tex]

= [tex] \frac{2611}{5200} [/tex]

Ans. [tex] \frac{2611}{5200} [/tex]

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