Raquelidn
Answered

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need answer,,,,
please solve for the value by using quadratic equation or formula and then getting the root 1 and 2
given: x^2-nx+n^2  
please show your solution,ty
thanks a lot ^_^

Sagot :

AnneCidn
[tex]x= \frac{-b +- \sqrt{b^2-4ac} }{2a} [/tex]

where ax² + bx + c = 0

For  x² -nx + n²
a = 1
b = -n
c = n²

Substitute to formula:

[tex]x= \frac{n +- \sqrt{n^2-4(1)(n^2)} }{2(1)} [/tex]

[tex]x= \frac{n +- \sqrt{n^2-4n^2} }{2} [/tex]

[tex]x= \frac{n +- \sqrt{-3n^2} }{2} [/tex]

[tex]x= \frac{n +- n\sqrt{-3} }{2} [/tex]

[tex]\boxed{x_{1}= \frac{n +n\sqrt{-3} }{2}} [/tex]

[tex]\boxed{x_{2}= \frac{n -n\sqrt{-3} }{2}} [/tex]