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Six rectangles each with a common base width of 2 have lengths of 1,4,9,16,25, and 36. What is the sum of the areas of the six rectangles?

Sagot :

1*2=2
4*2=8
9*2=18
16*2=32
25*2=50
36*2=72
2+8+18+32+50+72=182
Common base width = 2 units

Area = Width × Length

Sum of the areas of the overlapping rectangles:
 = 2 units [(1 + 4 + 9 + 16 + 25 + 36) units]
 = 2 units (91 units)
 = 182 sq. units

The sum of the areas of the 6 rectangles is 182 sq units.