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What is the equation of the line which is parallel to the line and passes 3x – 5y = 5 through (3, -7)?

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Sagot :

Yuri2005idn

Answer:

[tex]y = \frac{3x}{5} + \frac{-44}{5}[/tex]

Step-by-step explanation:

SOLUTION:

Step 1:

Find the slope of the line that is parallel to 3x - 5y = 5 :

[tex]m = \frac{3}{5}[/tex]

Step 2: (the first picture)

Substitute [tex]\left \{ {{m=\frac{3}{5} } \atop {x=3}} \atop {{y = -7}} \right.[/tex] into

[tex]y = mx + b\\\\-7 = \frac{3}{5} (3)+ b\\\\\\-7 = \frac{3 x 3}{5} + b\\\\-7 = \frac{9}{5} + b\\\\-b = \frac{9}{5} + 7\\\\-b = \frac{9 + 35}{5} \\\\-b = \frac{44}{5}\\\\b = - \frac{44}{5}[/tex]

Step 3: (the second picture)

Substitute [tex]\left \{ {{m=\frac{3}{5} } \atop {b=- \frac{44}{5} }} \right.[/tex]  into

y = mx + b :

[tex]y = \frac{3x}{5} + \frac{-44}{5}[/tex]

View image Yuri2005
View image Yuri2005
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