[tex]\tt{\huge{\red{Solution:}}}[/tex]
Step 1: Assume that the mass of solution is 100 g.
[tex]\begin{aligned} & \text{mass of solute} = \text{38 g} \\ & \text{mass of solvent} = \text{62 g = 0.062 kg} \end{aligned}[/tex]
Step 2: Calculate the number of moles of solute (C₃H₈O₃).
Note that the molar mass of C₃H₈O₃ is 92.09 g/mol.
[tex]\begin{aligned} \text{moles of solute} & = \frac{\text{mass of solute}}{\text{molar mass of solute}} \\ & = \frac{\text{38 g}}{\text{92.09 g/mol}} \\ & = \text{0.41264 mol} \end{aligned}[/tex]
Final Step: Calculate the molality of solution.
Note that 1 molal (m) is equal to 1 mole per kilogram (mol/kg).
[tex]\begin{aligned} \text{molality} & = \frac{\text{moles of solute}}{\text{mass of solvent}} \\ & = \frac{\text{0.41264 mol}}{\text{0.062 kg}} \\ & = \text{6.66 mol/kg} \\ & = \boxed{6.66 \: m} \end{aligned}[/tex]
Hence, the molality of the solution is 6.66 m.
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Note: Kindly swipe the screen to the left to see the continuation on the right side.
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