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1. A 457 L sample of gas with a pressure of 9.25 atm was placed in a container under a pressure of 12.5 atm. What is the new volume of the gas if its temperature remained constant at 378 K?
2. What pressure must be applied to a sample of Freon gas, an ozone-depleting substance, having a volume of 325 L at 20.0°C and 723 Torr to permit the expansion of the gas to a volume of 975L at 20.0°C?

(Include what’s the equation and required needed aside from only solution and final answer show. I don’t mind if either picture or typed in.)

Sagot :

Jaysonmarano09idn

Answer:

Boyle's Law

P1V1 = P2V2

where in, P1 = first pressure

V1 = first volume

P2 = second pressure

V2 = second volume

Given: P1 = 9.25atm

V1 = 457L

P2 = 12.5atm

Unknown: V2 = ?

Formula: V2 = P1V1 / P2

Note: Apply division and cancellation of like terms to get the formula, using the original formula of Boyle's Law.

• P1V1 = P2V2 ← divide both sides by P2

• P1V1 / P2 = P2V2 / P2 ← cancel like

terms

• P1V1 / P2 = V2 ← final formula

Explanation:

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